how do u do this??

The region bounded by y=x^3, y=0, and x=1 is rotated around the line x=-1. Find the volume of the resulting solid?

2/4/2009 10:12:25 PM

you're fucked

drop out of engineering now if you cant do this

2/4/2009 10:13:36 PM

no its for my cousin he asked me and i cant remember how to do it

[Edited on February 4, 2009 at 10:16 PM. Reason : left it out]

2/4/2009 10:15:26 PM

^ i don't believe you.

2/4/2009 11:45:08 PM

integrate that ish.

2/5/2009 9:44:05 AM

you integrate y=x³ with respect to y
the lower bound of y is given as 0 from y=0
the upper bound is found from y(1)=(1)³=1

solve y=x³ for x: x=y^(1/3)
outer radius=1-(-1)=2
inner radius=y^(1/3)-(-1)=y^(1/3)+1
*-1 is subtracted from the outer and inner radii to remove the area from -1 to 0 since you are only looking at 0 to 1.

V=integrate from 0 to 1 (outer radius)²-(inner radius)² dy

2/5/2009 12:03:43 PM

Don't forget the pi.

2/5/2009 5:45:04 PM

or the sigma bonds

2/5/2009 7:20:25 PM

WELCOME TO CHEMULUS

2/5/2009 7:23:18 PM

i did this in high school

I'm Big Business and i approved this message.

2/5/2009 8:05:06 PM

dont even remember how to do this garbage, as its pretty much useless after 241 anyway.

2/5/2009 8:37:49 PM

yep, and if by chance you need it for something you'll look it up in a book

[Edited on February 5, 2009 at 8:39 PM. Reason : so, it's like most everything else they teach you]

2/5/2009 8:39:08 PM

Goddamnit I don't remember shit, then again I learned this 6 years ago and mcfluffles response seems somewhat familiar, BUT I DON'T REMEMBER SHIT.

2/8/2009 1:55:59 PM

think about it logically.

Your integrand is just another dimension. Draw your normal X,Y like every math problem since 5th grade then plane then draw the z=0 overhead plane. This is likely to be completely useless whatever engineering you have, but it definitely shouldn't be hard. Calc 3 will be very difficult for you.

I'm Big Business and i approved this message.

2/9/2009 2:02:41 AM