Can anyone help me solve for theta:

(15/29)=(3* cot^2 (theta/2)-1)/4

Thanks



[Edited on November 2, 2005 at 9:29 PM. Reason : ..]

[Edited on November 2, 2005 at 9:31 PM. Reason : ...]

11/2/2005 9:28:25 PM

i got theta to be 89.3489 degrees

performed simple math operations to get 1.02299 = cot^2 (x/2)

cot = (1 / tan x)

1.02299 = (1 / tan (x/2))^2

sqrt(1.02299) = 1 / tan (x/2)

tan x/2 = .988699

x = 89.3489

[Edited on November 2, 2005 at 9:55 PM. Reason : more]

11/2/2005 9:41:54 PM

not sure exactly what you want is it just cot(theta/2) ^2?

x:=(15/29)=(3* cot(theta/2)^2-1)/4;solve(x,theta);

15 2
x := -- = 3/4 cot(1/2 theta) - 1/4
29


2 Pi - 2 arccot(1/87 sqrt(7743)), 2 arccot(1/87 sqrt(7743))

> 2*Pi-2*arccot(1/87*sqrt(7743)), 1.5594324458484273167;

2 Pi - 2 arccot(1/87 sqrt(7743)), 1.5594324458484273167

> 4.7237528613311591603, 2*arccot(1/87*sqrt(7743));

4.7237528613311591603, 2 arccot(1/87 sqrt(7743))


[Edited on November 2, 2005 at 9:50 PM. Reason : formatting all fucked up]

11/2/2005 9:47:14 PM

Thanks, I wasn't sure if you could take the square root of the cot^2 or not. And I didn't have an arc-cotan button on my calculator.

11/2/2005 10:33:20 PM

1.5594324458484273167 radians to degrees = 89.3488558 degrees

or

4.7237528613311591603 radians to degrees = 270.651102 degrees

11/3/2005 1:58:09 AM