The tert-Butyl group (C4H9) is a very bulky group. If this group is substituted for a H on Cyclohexane

would it have a strong preference to be equatorial or axial?

As we twist a model of n-Butane around the C2-C3 bond by 360°, how many energy maxima do we produce? Remember, 0° = 360°

im thinking 1 because it looks like a z and when u turn one carbon it reaches the energy maxima when it looks like a n but i only have 1 sub left and it could be 2 or 3.

1/27/2006 8:33:48 PM

always equitorial

1/27/2006 10:26:26 PM

all groups have a desire to be equatorial alone, it is when you also have a second group that comes in to play that you may have competition for the whole axial equatorial thing... if u stop by the tutorial center they'll help u, im there on on monday at 4 or weds at 11

[Edited on January 28, 2006 at 1:03 PM. Reason : ..]

1/28/2006 1:03:40 PM

^thanks and ^^ thanks

A tertiary-Butyl group, when attached to an oxygen atom in a complicated organic compound will contain

a three primary carbons and one tertiary carbon
b four 3° carbons
c a 1° C; a 2° C; a 3° C; and, a 4° C
d four 1° carbons
e three 3° carbons and one 1° carbon
f one methyl group, and a lot of other undefined carbons

[Edited on January 29, 2006 at 7:34 PM. Reason : last one]

1/29/2006 7:11:54 PM

G: Duke sucks

1/29/2006 8:41:18 PM

Okay. Tertiary butyl group will have a central carbon attached to 3 carbons.

now you just count how many carbons each other carbon is attached to.

any carbon attached to only one carbon is 'primary', etc etc. So just draw the structure and count?

thats the best i can do w/o giving the answer or w/o knowing what part in particular is confusing you.

[Edited on January 29, 2006 at 9:04 PM. Reason : fdafsa]

1/29/2006 8:52:55 PM