the floor of a railroad flatcar is loaded with loose crates having a coeffecient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

10/30/2007 9:37:32 PM

Do your own homework.

10/30/2007 10:19:06 PM

^ftw

study harder.

F=ma

given v, and mu

want displacement, know a=const.

10/30/2007 10:22:45 PM

LMAO, BIAAAATCH

10/30/2007 10:45:46 PM

^i aint seen you post in forever

10/30/2007 10:50:04 PM

Josh! My man...how ya been, dawg

10/30/2007 10:50:51 PM

not too bad...doing pretty well this semester...how bout u?

10/30/2007 11:17:03 PM

Quote :

"Class : Junior Major : CEM"

10/30/2007 11:17:25 PM

LOL i love it

10/31/2007 7:20:58 AM

fast as you want because the crate is up against a wall. Done.

10/31/2007 8:44:04 PM

study harder.

11/2/2007 12:56:12 AM

A: It doesn't matter. Railroads don't ship loose crates on flatcars. Too much risk of damage to the car or the freight.

I work in the rail industry, so my answer is official.

11/2/2007 9:58:57 PM

what i wanna know is why a train would "accelerate" to a stop..
isn't that slowing down to top speed

srsly, don't ask someone to just do a homework question for you. at least try.

11/3/2007 6:48:48 PM

^acceleration in the negative direction

11/3/2007 6:58:36 PM

Actually, it's not acceleration in the negative direction, it's acceleration in the direction opposing the current velocity. If the train's velocity is in the negative direction, positive acceleration will slow it down.

11/3/2007 7:05:20 PM

touche...a much more appropriate way of stating it

11/3/2007 7:16:40 PM