TenaciousC All American 6307 Posts user info edit post |
I'm having trouble naming these... which sucks, since I thought I had them all right
Can anyone tell me what I'm doing wrong?
12/7/2007 3:01:39 PM |
tough90zx Veteran 266 Posts user info edit post |
The first structure is another isomer of butane called isobutane. n-butane would be the normal chain of 4 carbons. 12/7/2007 3:10:06 PM |
DaveOT All American 11945 Posts user info edit post |
For several of those, you're not naming the structure, you're just counting carbons.
Read through http://chemistry.boisestate.edu/people/richardbanks/organic/nomenclature/alkanenomenclature1.htm 12/7/2007 3:10:47 PM |
tough90zx Veteran 266 Posts user info edit post |
On the second one you have a methyl off of both the 2nd and 3rd carbons. Count the longest chain of carbons, which is 4, and this is your parent. 2,3-dimethylbutane 12/7/2007 3:13:45 PM |
tough90zx Veteran 266 Posts user info edit post |
On the third one, make sure you put the branches in alphabetical order. 12/7/2007 3:17:43 PM |
tough90zx Veteran 266 Posts user info edit post |
On the 4th one, your longest chain of carbons is 3. The easiest way is to make the propene the parent and have a methyl group off of that. So you'd have 2-methylpropene. 12/7/2007 3:22:41 PM |
tough90zx Veteran 266 Posts user info edit post |
For the last one, you should always specify where the double bond is in an alkene. This is the cis isomer because both CH3 groups are on the same side. You specify the location of the double bond like this cis-but-2-ene. 12/7/2007 3:29:57 PM |
tough90zx Veteran 266 Posts user info edit post |
Let me know if I explained them well enough. 12/7/2007 3:30:20 PM |
evan All American 27701 Posts user info edit post |
hah, was gonna help in this thread but it looks like it's already been covered.
i <3 organic 12/7/2007 3:43:05 PM |
tough90zx Veteran 266 Posts user info edit post |
Tenacious, if you have any other questions before your final, post them in here and we'll try to answer. 12/7/2007 4:03:41 PM |
ncsukat All American 1896 Posts user info edit post |
tough90zx, I don't need to know for hw or anything & it has been years since I've fathomed looking at organic compounds... however, I've followed everything up until the part with the double bond. If you get a chance, would you mind explaining that again? Thanks! 12/7/2007 4:10:24 PM |
tough90zx Veteran 266 Posts user info edit post |
If you have an alkene, say for instance, pent-3-ene. The 3 is specifying the carbon on which the double bond starts. So you would have a 5 carbon chain and you would have the double bond between carbons 3 and 4. Doesn't matter from which end you start the numbering. 12/7/2007 4:13:18 PM |
tough90zx Veteran 266 Posts user info edit post |
When the double bond is not between carbons 1 and 2, you have to worry about cis and trans isomers also. 12/7/2007 4:17:25 PM |
TenaciousC All American 6307 Posts user info edit post |
Thanks for all the help! I'm at work now, but I'm going to try these again when I get home. 12/7/2007 5:05:24 PM |
roddy All American 25834 Posts user info edit post |
bttt 1/19/2008 3:08:01 PM |