7/25/2009 4:20:32 PM

haha

7/25/2009 4:22:11 PM

ahahaha

7/25/2009 4:23:11 PM

lol

7/25/2009 4:25:19 PM

haha

7/25/2009 4:51:11 PM

7/25/2009 8:35:47 PM

7/25/2009 8:37:01 PM

hahahahaha lmao

7/25/2009 8:37:07 PM

^^ha now thats good

[Edited on July 25, 2009 at 8:37 PM. Reason : .]

7/25/2009 8:37:13 PM

hahahahaha

7/25/2009 9:11:34 PM

bttt for night

7/26/2009 12:40:48 AM

the real component would just be 0 wouldnt it...?

7/26/2009 12:52:02 AM

^ it begins.

7/26/2009 12:56:08 AM

i <3 this thread

You just can't have inequalities with imaginary numbers

7/26/2009 1:43:51 AM

Here's why: https://en.wikipedia.org/wiki/Ordered_field#Which_fields_can_be_ordered.3F

Basically, in every ordered field, every nonzero number is either negative (less than 0) or positive (greater than 0), and multiplying both sides of an inequality by a negative number changes its sense; this means that all nonzero square numbers are less than 0, and 0 cannot be expressed as a sum of nonzero squares, but because it is possible to express 0 as the sum of nonzero squares of complex numbers (i^2+1^2=0), the complex numbers cannot be ordered.

9/29/2013 6:19:18 PM