I am listening to death metal on my way to get a pedicure.

7/17/2010 5:36:15 PM

you have a cock yet like cock

7/17/2010 5:37:14 PM

can't
won't
shouldn't


oh whoops...wrong thread

for this thread: Scotch Koreans

7/17/2010 6:31:18 PM

ShawnaC123 being happily married.

7/17/2010 6:32:50 PM

that would be a hell of a contradiction if it ever happened

7/17/2010 6:39:13 PM

Shawna, will you marry me?

7/17/2010 6:39:57 PM

only if you'll sign a prenup

7/17/2010 6:40:35 PM

i believe slave won

7/17/2010 6:41:26 PM

agreed.

7/17/2010 6:41:27 PM

Every set either contains itself or does not. Most sets do not contain themselves; as an example of a set which does, consider an image in a pair of opposing mirrors, so that each image contains, in theory, infinitely many copies of itself.

We now let K be the set of all sets which do not contain themselves. The question now arises, does K contain itself, i.e. is K a member of K? If so, then since K is defined by the property that none of its members contain themselves, K does not in fact contain itself, despite the fact that we assumed it did. But then K isn't a member of K, and since K contains everything that doesn't contain itself, we must conclude that K contains itself after all.

R.I.P. Bertrand Russell 1872-1970

7/17/2010 6:59:14 PM

SERIOUSLY EVAN

YOUR TOES WERE MORE IMPORTANT THAN MY GOING AWAY PARTY

7/17/2010 11:31:52 PM

^ I'm sure they were.

7/17/2010 11:40:52 PM

Microsoft Works

7/17/2010 11:48:14 PM