I'm sure this is very simple. I've gotten most of them. However I'm stuck on a couple. Can anyone point me in the right direction?

find the pH of 10.0 mL deionized water plus 10.0 mL of 0.1 M NaOH


Thanks.

2/26/2007 5:20:21 PM

I'll bet it's >7

2/26/2007 5:22:41 PM

That's a pretty good guess. Considering water is 7. However, I need something more accurate. Thanks anyway

2/26/2007 5:27:54 PM

This is basic and normally I would tell you to read a book for die in a fire, but I'm in a helpful mood.

You have 0.1M OH-

You have 0.2 L total solution

Thus you have 0.05 M/L

Given:

log(0.05) = ~-1.3 OH- concentration

14 + (-1.3) = 12.7 pH

There's always the possibility I fucked this up. It's been a long time and I'm not a chemist.

2/26/2007 5:47:21 PM