say i have something like:

(making up #'s here so they might not work out)
16=log(.5x)+log(.1x)

how do i solve for x?

11/19/2007 11:14:48 PM

flush 'em

11/19/2007 11:15:12 PM

I usually pinch them off in the toilet.

11/19/2007 11:15:19 PM

it's big, it's heavy, it's MATHEMATICS

11/19/2007 11:15:59 PM

e

or inverse of log

?

i done forgot sir

11/19/2007 11:15:59 PM

^ nah man, e is for natural logs

base 10 that motherfucker

11/19/2007 11:18:26 PM

you mean 10^x that bitch

Quote :

"it's big, it's heavy, it's MATHEMATICS"

11/19/2007 11:19:26 PM

aaahh yeah.

base 10.

true.

11/19/2007 11:20:22 PM

^^that is exactly what I meant

that motherfucker is base 10

[Edited on November 19, 2007 at 11:21 PM. Reason : UNDO IT]

11/19/2007 11:20:44 PM

well base 10 would just be putting the number into base 10

which it already should be

11/19/2007 11:21:24 PM

16=log(.5x)+log(.1x)

10^(16) = 10^(log(.5x*.1x))

10^(16) = (.5x*.1x)

solve for x

11/19/2007 11:22:20 PM

pfffffffft

11/19/2007 11:24:39 PM

also, burn them

11/19/2007 11:25:28 PM

^burn them

11/19/2007 11:27:23 PM

Quote :

"flush 'em"

winner

11/19/2007 11:28:25 PM

clearcut and burn a forest

11/19/2007 11:29:11 PM

Walter is a moron

11/19/2007 11:30:41 PM

Get a calculator.

11/19/2007 11:52:40 PM

thanks StillFuchsia, now my brain hurts

11/20/2007 12:14:56 AM

you're welcome

11/20/2007 12:25:59 AM

someone didnt pay attention in 8th grade algebra.

11/20/2007 12:28:14 AM

now just solve this equation explicitly

xln(x)=17

11/20/2007 12:39:13 AM

^ hahahaha

11/20/2007 12:43:11 AM

^^gg

11/20/2007 12:52:24 AM

if people paid attention in class this all would never have happened...

11/20/2007 2:07:41 AM

^if noobs would STFU then that would never have happened...

11/20/2007 2:08:20 AM

11/20/2007 2:08:40 AM

11/20/2007 2:16:12 AM