ok so i am having a hard time with taylor series...

ok a problem in my book says find the Taylor series at x=0 of (1/(2x+3)) by computing three or four derivatives and using the definition of the Taylor series.

then the answer is 1/3 -2/9x + (2^2/3^3) x^2 - (2^3/3^4)x^3...

but i have no idea how to get this or why you switch the signs off..

if someone would help me i would really appreciate it.

Thanks!

10/16/2008 11:42:16 PM

find the first through fourth derivatives then set x=0 and then plug it into the taylor series

f(0) + f1(0)/1! + (f2(0)/2!)x^2 etc

10/16/2008 11:49:12 PM

http://mathworld.wolfram.com/TaylorSeries.html

10/20/2008 6:44:48 AM

taylor series and taylor's theorem are so damn useful.

10/21/2008 1:43:56 AM

^ yes they are.

10/21/2008 12:48:49 PM